Question(2 points) Let $f(x)=7+\sqrt{x-9}$. Then find each of the following, giving all domain (a) $f^{-1}(x)=$ $\square$ (b) The domain of $f$ is $\square$ (c) The domain of $f^{-1}$ is $\square$ (d) The range of $f$ is $\square$ (e) The range of $f^{-1}$ is $\square$

Studdy Solution
The range of $f^{-1}(x)$ is the domain of $f(x)$, which is:
$$[9, \infty)$$
The solutions are: (a) $f^{-1}(x) = (x - 7)^2 + 9$ (b) The domain of $f$ is $[9, \infty)$ (c) The domain of $f^{-1}$ is $[7, \infty)$ (d) The range of $f$ is $[7, \infty)$ (e) The range of $f^{-1}$ is $[9, \infty)$