Math  /  Algebra

Question2. Δ\Delta ivovta ol σuvαρtησεıς\sigma u v \alpha \rho t \eta ่ \sigma \varepsilon ı \varsigma φ(x)=2x2,f(x)=2x2+8x+11καg(x)=2x28x11\varphi(x)=2 x^{2}, f(x)=2 x^{2}+8 x+11 \kappa \alpha \prime g(x)=-2 x^{2}-8 x-11 II. NaN a סıкаюдоү III. NαδεiξτεN \alpha \delta \varepsilon i \xi \tau \varepsilon ó τf(x)=2(x+2)2+3,xR\tau \mathrm{f}(\mathrm{x})=2(\mathrm{x}+2)^{2}+3, \mathrm{x} \in \mathbb{R}. (Mová δ\delta ec 1+2+2+2+2+1)

Studdy Solution
Αποδείξαμε ότι f(x)=2(x+2)2+3f(x) = 2(x+2)^2 + 3.
Υπολογίσαμε την f(2)=3f(-2) = 3.
Δείξαμε ότι η φ(x)\varphi(x) είναι συμμετρική ως προς τον άξονα y.

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