Math  /  Trigonometry

Question2cos2x2sin2x=12 \cos ^{2} x-2 \sin ^{2} x=1

Studdy Solution
The solutions to the equation 2cos2x2sin2x=12 \cos ^{2} x-2 \sin ^{2} x=1 are x=π6+nπx = \frac{\pi}{6} + n\pi and x=5π6+nπx = \frac{5\pi}{6} + n\pi, where nn is any integer.

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