Question2. $3(x+1)^{2}-3=0$ . .xis of symmetry: Vertex: Solution(s):

Studdy Solution
The solutions to the equation $3(x+1)^2 - 3 = 0$ are $x=0$ and $x=-2$.
The axis of symmetry is $x=-1$, and the vertex is at $(-1, -3)$.