Math  /  Algebra

QuestionSolve for xx by completing the square: x27x=12x^{2}-7 x=-12. Also, find xx and yy for y2x+4=0y-2 x+4=0 and x2+y=4x^{2}+y=4.

Studdy Solution
Substitute x=2x =2 and x=x = - into the equation y=2xy =2x - to solve for yy.
For x=2x =2, y=2(2)=0y =2(2) - =0. For x=x = -, y=2()=12y =2(-) - = -12.
So the solutions are (2,0)(2,0) and (,12)(-, -12).

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