Math  /  Algebra

Question17. r2s=04r3s=15\begin{aligned} r-2 s & =0 \\ 4 r-3 s & =15\end{aligned}

Studdy Solution
Verificamos la solución en ambas ecuaciones originales:
Primera ecuación:
r2s=0 r - 2s = 0 62(3)=0 6 - 2(3) = 0 66=0 6 - 6 = 0
Segunda ecuación:
4r3s=15 4r - 3s = 15 4(6)3(3)=15 4(6) - 3(3) = 15 249=15 24 - 9 = 15
Ambas ecuaciones son correctas.
La solución es r=6 r = 6 y s=3 s = 3 .

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