Math  /  Algebra

Question16\mathbf{1 6} to 20\mathbf{2 0} refer to the vector equation Ax=λx\mathbf{A} \cdot \mathbf{x}=\lambda \mathbf{x}. For the coefficient matrix A\mathbf{A} given in each case, determine the eigenvalues and an eigenvector corresponding to each eigenvalue: 16A=(211132112)16 \quad \mathbf{A}=\left(\begin{array}{rrr}2 & 1 & 1 \\ 1 & 3 & 2 \\ -1 & 1 & 2\end{array}\right) 17A=(122131221)17 \mathbf{A}=\left(\begin{array}{lll}1 & 2 & 2 \\ 1 & 3 & 1 \\ 2 & 2 & 1\end{array}\right) 18A=(201141120)18 \quad \mathbf{A}=\left(\begin{array}{rrr}2 & 0 & 1 \\ -1 & 4 & -1 \\ -1 & 2 & 0\end{array}\right) 19A=(142031124)19 \mathbf{A}=\left(\begin{array}{rrr}1 & -4 & -2 \\ 0 & 3 & 1 \\ 1 & 2 & 4\end{array}\right) 20A=(303033231)20 \quad \mathbf{A}=\left(\begin{array}{lll}3 & 0 & 3 \\ 0 & 3 & 3 \\ 2 & 3 & 1\end{array}\right)

Studdy Solution
For each eigenvalue λ\lambda found, substitute it back into the equation (AλI)x=0(\mathbf{A} - \lambda \mathbf{I}) \mathbf{x} = \mathbf{0} and solve for the eigenvector x\mathbf{x}.
Example for Matrix 16: Assume λ1\lambda_1 is an eigenvalue, solve: (2λ11113λ12112λ1)(x1x2x3)=(000)\begin{pmatrix} 2-\lambda_1 & 1 & 1 \\ 1 & 3-\lambda_1 & 2 \\ -1 & 1 & 2-\lambda_1 \end{pmatrix} \begin{pmatrix} x_1 \\ x_2 \\ x_3 \end{pmatrix} = \begin{pmatrix} 0 \\ 0 \\ 0 \end{pmatrix}
Repeat the above steps for each matrix (17, 18, 19, 20) to find their eigenvalues and corresponding eigenvectors.

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