Question15. Solve $3 \sin 2 x-1=0$ on the interval $x \in[0,2 \pi]$.

Studdy Solution
Ensure all solutions for $x$ fall within the interval $[0, 2\pi]$:
Verify each calculated $x$ value is within the interval $[0, 2\pi]$.
The solutions for $x$ are approximately:
$$x = \frac{\arcsin\left(\frac{1}{3}\right)}{2}, \frac{\pi - \arcsin\left(\frac{1}{3}\right)}{2}, \frac{\arcsin\left(\frac{1}{3}\right) + 2\pi}{2}, \frac{\pi - \arcsin\left(\frac{1}{3}\right) + 2\pi}{2}$$