Math  /  Algebra

Question144y2x2=1144y^2 - x^2 = 1
Graph the hyperbola. Choose the correct graph below.
The foci is/are at the point(s) \square. (Type an ordered pair. Type an exact answer, using radicals as needed. Use a comma to separate answers as needed.)
The equation of the asymptote with the positive slope is \square. The equation of the asymptote with the negative slope is \square. (Simplify your answers. Use integers or fractions for any numbers in the equation.)

Studdy Solution
The foci are at (0,14512)(0, \frac{\sqrt{145}}{12}) and (0,14512)(0, -\frac{\sqrt{145}}{12}).
The equation of the asymptote with positive slope is y=112xy = \frac{1}{12}x.
The equation of the asymptote with negative slope is y=112xy = -\frac{1}{12}x.
The correct graph is **B**.

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