Math  /  Algebra

Question14 Mark for Review 420 F(x)=95(x273.15)+32F(x)=\frac{9}{5}(x-273.15)+32
The function FF gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of xx kelvins. If a temperature increased by 2.10 kelvins, by how much did the temperature increase, in degrees Fahrenheit? (A) 3.78 (B) 35.78 (C) 487.89 (D) 519.89

Studdy Solution
The temperature increased by **3.78** degrees Fahrenheit, which is answer choice (A).

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