Math  /  Numbers & Operations

Question12 g12amu=1 g1amu=1 g1.661024 g=60221023\frac{12 \mathrm{~g}}{12 \mathrm{amu}}=\frac{1 \mathrm{~g}}{1 \mathrm{amu}}=\frac{1 \mathrm{~g}}{1.66 \cdot 10^{-24} \mathrm{~g}}=6022 \cdot 10^{23}

Studdy Solution
Verify the calculation:
The calculation confirms that 1 g 1 \text{ g} of a substance contains approximately 6.022×1023 6.022 \times 10^{23} atoms, aligning with Avogadro's number.
The equivalence and calculation verify the relationship between grams, amu, and Avogadro's number:
6.022×1023\boxed{6.022 \times 10^{23}}

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