Math

Question12-47 Determine the true power and the reactive power in the previous question. True porer is ideally o W.  Meactive power =Imss2Xc=Irms22πfc=3.4nVAR\text { Meactive power }=I_{\mathrm{mss}}^{2} X_{c}=\frac{I_{\mathrm{rms}}^{2}}{2 \pi \mathrm{fc}}=3.4 \mathrm{nVAR}

Studdy Solution
Verify the calculations:
- True power is confirmed as 0W0 \, \text{W} for an ideal reactive circuit. - Reactive power is confirmed as 3.4nVAR3.4 \, \text{nVAR}.
The true power is 0W \boxed{0 \, \text{W}} and the reactive power is 3.4nVAR \boxed{3.4 \, \text{nVAR}} .

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