Math  /  Algebra

Question11 Given $250,000\$ 250,000 today, determine the equivalent series of 10 annual payments which could be generated beginning in 1 year. Assume interest is 12 percent compounded annually.

Studdy Solution
Solve for the annual payment P P .
First, calculate (1+0.12)10 (1 + 0.12)^{-10} :
(1.12)100.3220 (1.12)^{-10} \approx 0.3220
Next, calculate the annuity factor:
10.32200.120.67800.125.6500 \frac{1 - 0.3220}{0.12} \approx \frac{0.6780}{0.12} \approx 5.6500
Now, solve for P P :
250,000=P×5.6500 250,000 = P \times 5.6500
P=250,0005.6500 P = \frac{250,000}{5.6500}
P44,247.79 P \approx 44,247.79
The equivalent series of 10 annual payments is approximately:
44,247.79 \boxed{44,247.79}

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