Math  /  Algebra

Question11. Galoulate the determinant. [5231]\left[\begin{array}{ll} 5 & 2 \\ 3 & 1 \end{array}\right] 1 11 0 11-11 1-1

Studdy Solution
Substitute the identified elements into the formula and calculate:
det=(5)(1)(2)(3) \text{det} = (5)(1) - (2)(3) det=56 \text{det} = 5 - 6 det=1 \text{det} = -1
The determinant of the matrix is:
1 \boxed{-1}

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