Question10. $\left\{\begin{array}{l}6 x-3 y=12 \\ 4 x-3 y=24\end{array}\right.$

Studdy Solution
Verify the solution by substituting $x = -6$ and $y = -16$ into both original equations.
For Equation 1:
$6(-6) - 3(-16) = 12$
$-36 + 48 = 12$
This is true.
For Equation 2:
$4(-6) - 3(-16) = 24$
$-24 + 48 = 24$
This is also true.
Both equations are satisfied, so the solution is verified.
The solution to the system of equations is $x = -6$ and $y = -16$.