Math  /  Algebra

Question1) What is the series of the sequence {1,4,7,10,13}\{1,4,7,10,13\} ? \square Check Show answer 2) What is a10a_{10} for the sequence {2,6,10,}\{2,6,10, \ldots\} ? \square Check Show answer 3) What is S10S_{10} for the sequence {2,6,10,}\{2,6,10, \ldots\} ? \square Check Show answer. 4) What is n=1203n\sum_{n=1}^{20} 3 n ? \square Check Show answer

Studdy Solution
Evaluate n=1203n\sum_{n=1}^{20} 3n. Recognize this as an arithmetic series where each term is 3n 3n . The sum of the first 20 20 terms can be calculated as:
n=1203n=3n=120n \sum_{n=1}^{20} 3n = 3 \sum_{n=1}^{20} n
The sum of the first n n natural numbers is n(n+1)2\frac{n(n+1)}{2}, so:
n=120n=20×212=210 \sum_{n=1}^{20} n = \frac{20 \times 21}{2} = 210
Thus:
n=1203n=3×210=630 \sum_{n=1}^{20} 3n = 3 \times 210 = 630
The solutions are: 1) Series: an=1+(n1)×3 a_n = 1 + (n-1) \times 3 2) a10=38 a_{10} = 38 3) S10=200 S_{10} = 200 4) n=1203n=630\sum_{n=1}^{20} 3n = 630

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