Math  /  Calculus

Question(1 point) When air expands adiabatically (without gaining or losing heat), its pressure PP and volume VV are related by the equation PV1.4=CP V^{1.4}=C where CC is a constant. Suppose that at a certain instant the volume is 530 cubic centimeters and the pressure is 93 kPa and is decreasing at a rate of 11kPa/11 \mathrm{kPa} / minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?
Answer: \square Note: Pa stands for Pascal One PaP a is equivalent to one Newton /m2kPa/ \mathrm{m}^{2} \cdot k P a is a kiloPascal or 1000 Pascals.

Studdy Solution
The rate at which the volume is increasing is dVdt=115301.4931.45300.4\frac{dV}{dt} = \frac{11 \cdot 530^{1.4}}{93 \cdot 1.4 \cdot 530^{0.4}} cubic centimeters per minute.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord