Question1 point
Given $\bar{p}=2 x+1 x^{2}$, find the norm of $p$

Studdy Solution
Calculate the norm using the identified coefficients:
$$\| \bar{p} \| = \sqrt{2^2 + 1^2}$$ $$\| \bar{p} \| = \sqrt{4 + 1}$$ $$\| \bar{p} \| = \sqrt{5}$$
The norm of the vector $\bar{p}$ is:
$$\boxed{\sqrt{5}}$$