Math / CalculusQuestion(1 point) Evaluate the definite integral. ∫−6−4(x+4)ex2+8x+15dx=\int_{-6}^{-4}(x+4) e^{x^{2}+8 x+15} d x=∫−6−4(x+4)ex2+8x+15dx= □\square□Studdy SolutionThe value of the definite integral is 1−e42e\frac{1 - e^4}{2e}2e1−e4.View Full Solution - FreeWas this helpful?
