Math / AlgebraQuestion1 Find the slant asymptote of the function f(x)=x2+4x−8x+3f(x)=\frac{x^{2}+4 x-8}{x+3}f(x)=x+3x2+4x−8 ?Studdy SolutionThe slant asymptote of the function f(x)=x2+4x−8x+3f(x) = \frac{x^2 + 4x - 8}{x + 3}f(x)=x+3x2+4x−8 is y=x+1y = x + 1y=x+1.View Full Solution - FreeWas this helpful?
