Math  /  Algebra

Question1. A football player pushed a 75 kg blocking sled with a constant horizontal force of 400 N . The coefficient of kinetic friction between the sled and ground is 0.3 . How much horizontal force opposes the forward motion of the sled? What is the sled's horizontal acceleration? (Assume that the playing surface is level).

Studdy Solution
Calculate the sled's horizontal acceleration using Newton's second law.
Newton's second law states:
Fnet=m×a F_{\text{net}} = m \times a
where a a is the acceleration. Rearrange the equation to solve for a a :
a=Fnetm a = \frac{F_{\text{net}}}{m} a=179.5N75kg a = \frac{179.5 \, \text{N}}{75 \, \text{kg}} a=2.3933m/s2 a = 2.3933 \, \text{m/s}^2
The sled's horizontal acceleration is approximately 2.39m/s2 2.39 \, \text{m/s}^2 .

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