Math / Data & StatisticsQuestion∨1\vee 1∨1 12 3 4 5 6 ✓7\checkmark 7✓7 78If P(A)=0.51,P(B)=0.6P(A)=0.51, P(B)=0.6P(A)=0.51,P(B)=0.6, and P(AP(AP(A and B)=0.41B)=0.41B)=0.41, find P(AP(AP(A or B)B)B). P(A or B)=P(A \text { or } B)=P(A or B)= □\square□ □\square□Studdy SolutionPerform the calculation:P(A or B)=1.11−0.41=0.70 P(A \text{ or } B) = 1.11 - 0.41 = 0.70 P(A or B)=1.11−0.41=0.70 The probability P(A or B) P(A \text{ or } B) P(A or B) is:0.70 \boxed{0.70} 0.70View Full Solution - FreeWas this helpful?