Math

Question02010.0 points A(n)59 kg\mathrm{A}(\mathrm{n}) 59 \mathrm{~kg} astronaut becomes separated from the shuttle, while on a space walk. She finds herself 46.3 m away from the shuttle and moving with zero speed relative to the shuttle. She has a(n) 0.575 kg camera in her hand and decides to get back to the shuttle by throwing the camera at a speed of 12 m/s12 \mathrm{~m} / \mathrm{s} in the direction away from the shuttle.
How long will it take for her to reach the shuttle? Answer in minutes.
1. 3.629 min
2. 5.609 min
3. 3.959 min
4. 5.938 min
5. 4.619 min
6. 4.289 min
7. 4.949 min

Studdy Solution
Calculate the time it takes for the astronaut to reach the shuttle using the formula:
Time=DistanceSpeed \text{Time} = \frac{\text{Distance}}{\text{Speed}}
Substitute the values:
Time=46.3m0.11695m/s \text{Time} = \frac{46.3 \, \text{m}}{0.11695 \, \text{m/s}}
Time=395.96s \text{Time} = 395.96 \, \text{s}
Convert time from seconds to minutes:
Time=395.96s60s/min \text{Time} = \frac{395.96 \, \text{s}}{60 \, \text{s/min}}
Time6.599min \text{Time} \approx 6.599 \, \text{min}
The time it takes for the astronaut to reach the shuttle is approximately:
6.599min \boxed{6.599 \, \text{min}}

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