Math  /  Algebra

Question0t40 \leq t \leq 4 \text {. }
2. Find the corresponding rectangular equation of the following parametric equations: a. x=2t3,y=3t+1x=2 t-3, y=3 t+1 b. x=t3,y=t22x=t^{3}, y=\frac{t^{2}}{2} c. x=secθ,y=cosθx=\sec \theta, y=\cos \theta

Studdy Solution
Substitute cosθ=1x \cos \theta = \frac{1}{x} into the equation for y y :
y=cosθ y = \cos \theta y=1x y = \frac{1}{x}
The corresponding rectangular equations are: a. y=3x+112 y = \frac{3x + 11}{2} b. y=x2/32 y = \frac{x^{2/3}}{2} c. y=1x y = \frac{1}{x}

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